The number of valence electrons in Fe^{2+} io | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The atomic number of $Fe$ is $26$. The electronic configuration of neutral $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms an $Fe^{2+}$ ion,it loses two

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) The atomic number of $Fe$ is $26$. The electronic configuration of neutral $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms an $Fe^{2+}$ ion,it loses two electrons from the outermost $4s$ orbital.Thus,the electronic configuration of $Fe^{2+}$ becomes $[Ar] 3d^6$.The valence electrons are the electrons in the outermost shell or the partially filled $d$-subshell involved in bonding. For $Fe^{2+}$,the $3d$ electrons are considered valence electrons. There are $6$ electrons in the $3d$ subshell.

The number of valence electrons in $Fe^{2+}$ ion $(Fe = 26)$ is .......

Similar Questions

Which $d-$block element is expected to have the highest enthalpy of atomisation among the following?

Zinc and mercury do not show variable valency like $d-$block elements because

How many unpaired electrons are there in $Ni^{2+}$?

The calculated magnetic moment (in Bohr magnetons) of $Cu^{2+}$ ion is:

Why is the $E^{\Theta }$ value for the $Mn^{3+}/Mn^{2+}$ couple much more positive than that for $Cr^{3+}/Cr^{2+}$ or $Fe^{3+}/Fe^{2+}$? Explain.

Vedclass Test Series

Exam Paper Generator

Online Exam Module