For the reaction 2A + 3B rightarrow 4C,the ra | vedclass

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(D) For a general reaction $aA + bB \rightarrow cC + dD$,the rate of reaction is given by:$r = -\frac{1}{a}\frac{d[A]}{dt} = -\frac{1}{b}\frac{d[B]}{d

Vedclass · Accepted Answer

$r = -\frac{1}{2}\frac{d[A]}{dt} = -\frac{1}{3}\frac{d[B]}{dt} = \frac{1}{4}\frac{d[C]}{dt}$

Vedclass · Answer

(D) For a general reaction $aA + bB \rightarrow cC + dD$,the rate of reaction is given by:$r = -\frac{1}{a}\frac{d[A]}{dt} = -\frac{1}{b}\frac{d[B]}{dt} = \frac{1}{c}\frac{d[C]}{dt} = \frac{1}{d}\frac{d[D]}{dt}$Given the reaction $2A + 3B \rightarrow 4C$,the stoichiometric coefficients are $a=2$,$b=3$,and $c=4$.Substituting these values into the formula:$r = -\frac{1}{2}\frac{d[A]}{dt} = -\frac{1}{3}\frac{d[B]}{dt} = \frac{1}{4}\frac{d[C]}{dt}$Therefore,option $D$ is correct.

For the reaction $2A + 3B \rightarrow 4C$,the rate of reaction is expressed as:

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