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(A) The rate of reaction $(r)$ is defined as the rate of disappearance of reactants divided by their stoichiometric coefficients.For the reaction $2A

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$3r_1 = 2r_2$

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(A) The rate of reaction $(r)$ is defined as the rate of disappearance of reactants divided by their stoichiometric coefficients.For the reaction $2A + 3B ightarrow 	ext{Products}$,the rate is given by:$r = -\frac{1}{2} \frac{d[A]}{dt} = -\frac{1}{3} \frac{d[B]}{dt}$Given that the rate of disappearance of $A$ is $r_1 = -\frac{d[A]}{dt}$ and the rate of disappearance of $B$ is $r_2 = -\frac{d[B]}{dt}$,we substitute these into the expression:$r = \frac{1}{2} r_1 = \frac{1}{3} r_2$Multiplying by $6$,we get:$3r_1 = 2r_2$

For a general chemical reaction $2A + 3B \rightarrow \text{Products}$,if the rate of disappearance of $A$ is $r_1$ and that of $B$ is $r_2$,then the relationship between $r_1$ and $r_2$ is:

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