For the reaction $H_{2(g)} + Br_{2(g)} \rightarrow 2HBr_{(g)}$,the experimental data suggests the rate law is $\text{Rate} = K[H_2][Br_2]^{1/2}$. Find the order of the reaction and its molecularity.

  • A
    Order $2$ and molecularity $2$ respectively
  • B
    Order $1\frac{1}{2}$ and molecularity $2$ respectively
  • C
    Order $2$ and molecularity $1\frac{1}{2}$ respectively
  • D
    Order $1\frac{1}{2}$ and molecularity $1\frac{1}{2}$ respectively

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