Medium
If the concentration of reactant $B$ is doubled,the rate of the reaction between reactants $A$ and $B$ becomes $1/4$ of the initial rate. The order of the reaction with respect to reactant $B$ is ......
- A$-1$
- B$-2$
- C$1$
- D$2$
Explore More
Similar Questions
When the concentration of a reactant,$A$,in a reaction $A \to \text{Products}$ is doubled,the rate of reaction increases seven times. The order of the reaction is between:
Medium
View SolutionFor the reaction $A + 2B \to C$,the rate is given by $R = k[A][B]^2$. The order of the reaction is:
For a reaction $A + B \longrightarrow P$,the following data are provided. The rate constant for this reaction in standard units is:
Entry $[A]$ in $M$ $[B]$ in $M$ Initial rate $(M/s)$ $1$ $0.02$ $0.02$ $2 \times 10^{-2}$ $2$ $0.02$ $0.04$ $4 \times 10^{-2}$ $3$ $0.04$ $0.04$ $8 \times 10^{-2}$
| Entry | $[A]$ in $M$ | $[B]$ in $M$ | Initial rate $(M/s)$ |
|---|---|---|---|
| $1$ | $0.02$ | $0.02$ | $2 \times 10^{-2}$ |
| $2$ | $0.02$ | $0.04$ | $4 \times 10^{-2}$ |
| $3$ | $0.04$ | $0.04$ | $8 \times 10^{-2}$ |
DifficultTS EAMCET 2021
View SolutionWrite the unit of the rate constant for the following reactions:
$1.$ Fourth order
$2.$ Third order
$1.$ Fourth order
$2.$ Third order
Medium
View SolutionWrite the differential rate expression for the following reactions and determine their order of reaction:
$1) \ 2 N_2O_5(g) \rightarrow 4 NO_2(g) + O_2(g)$
$2) \ C_4H_9Cl(aq) + OH^-(aq) \rightarrow C_4H_9OH(aq) + Cl^-(aq)$
$1) \ 2 N_2O_5(g) \rightarrow 4 NO_2(g) + O_2(g)$
$2) \ C_4H_9Cl(aq) + OH^-(aq) \rightarrow C_4H_9OH(aq) + Cl^-(aq)$
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo