(A) The formula for the remaining mass of a radioactive substance is $N_t = N_0 \times (1/2)^n$,where $n$ is the number of half-lives.First,calculate

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(A) The formula for the remaining mass of a radioactive substance is $N_t = N_0 \times (1/2)^n$,where $n$ is the number of half-lives.First,calculate the number of half-lives $(n)$: $n = \frac{\text{Total time}}{\text{Half-life}} = \frac{18 \ h}{3 \ h} = 6$.Now,substitute the values into the formula: $N_t = 256 \ g \times (1/2)^6$.$N_t = 256 \times \frac{1}{64}$.$N_t = 4.0 \ g$.

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

Medium

The half-life of a radioactive isotope is $3 \ hours$. If the initial mass of the isotope is $256 \ g$,how much mass in $g$ will remain after $18 \ hours$ (in $.0$)?

A
$4$
B
$8$
C
$12$
D
$16$

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Nuclear Chemistry

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Rate of decay and Half-life

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The half-life of a radioactive isotope is $3 \ hours$. If the initial mass of the isotope is $256 \ g$,how much mass in $g$ will remain after $18 \ hours$ (in $.0$)?

Similar Questions

Decay of $_{92}U^{235}$ is $...$ order reaction.

The half-life of a radionuclide is $69.3 \text{ minutes}$. What is its average life (in minutes)?

$t_{1/2}$ of $^{232}Th$ is $1.39 \times 10^{10} \ \text{years}$. Calculate the number of $\alpha$-particles emitted by $1.0 \ \text{g}$ of $^{232}Th$ per second.

$1.0 \ g$ of radioactive sodium decays to $0.25 \ g$ in $16 \ hours$. Calculate the time required for $48 \ g$ of the same radioactive sodium to decay to $3.0 \ g$. (in $hours$)

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