(D) For a first-order reaction,the concentration decreases as follows: $1$ $\xrightarrow{t_{1/2}} 1/2$ $\xrightarrow{t_{1/2}} 1/4$ $\xrightarrow{t_{1/

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(D) For a first-order reaction,the concentration decreases as follows: $1$ $\xrightarrow{t_{1/2}} 1/2$ $\xrightarrow{t_{1/2}} 1/4$ $\xrightarrow{t_{1/2}} 1/8$ $\xrightarrow{t_{1/2}} 1/16$. Time taken to reach $1/4$ of initial concentration is $2 \times t_{1/2} = 20 \ min$,so $t_{1/2} = 10 \ min$. Time taken to reach $1/16$ of initial concentration is $4 \times t_{1/2} = 4 \times 10 \ min = 40 \ min$.

Class 12 Chemistry Chemical Kinetics First Order reaction

Medium

For a first-order reaction,the time taken for the initial concentration to decrease to $1/4$ of its value is $20 \ min$. The time taken for the initial concentration to decrease to $1/16$ of its value will be $......... \ min$.

A
$20$
B
$10$
C
$80$
D
$40$

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Chemical Kinetics

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First Order reaction

If the half-life $(t_{1/2})$ of a first-order reaction is $20 \ minutes$,what fraction of the reactant remains after $40 \ minutes$?

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In a first order reaction,the concentration of the reactant decreases from $20 \ mmol$ to $10 \ mmol$ in $1.151 \ min$. What is the rate constant (in $min^{-1}$)?

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If a $99\%$ first-order reaction is completed in $32$ minutes,how many minutes will it take for $99.9\%$ of the reaction to be completed?

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The rate constant of a first-order reaction is $6 \ min^{-1}$. If the initial concentration of the reactant is $0.5 \ mol \ L^{-1}$,after how many minutes will the concentration of the reactant become $0.05 \ mol \ L^{-1}$?

Medium

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For a first order reaction $R \longrightarrow P$,the rate constant is $k$. If the initial concentration of $R$ is $[R_0]$,the concentration of $R$ at any time $t$ is given by the expression:

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For a first-order reaction,the time taken for the initial concentration to decrease to $1/4$ of its value is $20 \ min$. The time taken for the initial concentration to decrease to $1/16$ of its value will be $......... \ min$.

Similar Questions

If the half-life $(t_{1/2})$ of a first-order reaction is $20 \ minutes$,what fraction of the reactant remains after $40 \ minutes$?

In a first order reaction,the concentration of the reactant decreases from $20 \ mmol$ to $10 \ mmol$ in $1.151 \ min$. What is the rate constant (in $min^{-1}$)?

If a $99\%$ first-order reaction is completed in $32$ minutes,how many minutes will it take for $99.9\%$ of the reaction to be completed?

The rate constant of a first-order reaction is $6 \ min^{-1}$. If the initial concentration of the reactant is $0.5 \ mol \ L^{-1}$,after how many minutes will the concentration of the reactant become $0.05 \ mol \ L^{-1}$?

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