Reactant $(A)$ produces two products. If $Ea_2 = 2 Ea_1$,then $K_1$ and $K_2$ are related as:
$A \xrightarrow{K_1} B$,activation energy: $Ea_1$
$A \xrightarrow{K_2} C$,activation energy: $Ea_2$
$A \xrightarrow{K_1} B$,activation energy: $Ea_1$
$A \xrightarrow{K_2} C$,activation energy: $Ea_2$
- A$K_1 = 2 K_2 e^{Ea_2/RT}$
- B$K_2 = K_1 e^{Ea_1/RT}$
- C$K_2 = K_1 e^{Ea_2/RT}$
- D$K_1 = A' K_2 e^{Ea_1/RT}$
Explore More
Similar Questions
Write the logarithmic form of the Arrhenius equation $k = A e^{-\frac{E_a}{RT}}$.
Easy
View Solution$A$ catalyst:
MediumIIT 1984
View SolutionThe first order rate constant $k$ is related to temperature $T$ as $\log \, k = 15.0 - (10^{6} / T)$. Which of the following pairs of values for the Arrhenius factor $A$ and activation energy $E_a$ is correct?
Medium
View SolutionFor a first-order reaction $A \to P$,the rate constant equation is given by $\log K = -2000 \, (1/T) + 6.0$. The pre-exponential factor $A$ and the activation energy $E_a$ are,respectively:
Medium
View SolutionWhat is the relationship between the temperature $T$ and the activation energy $E_a$ in the Arrhenius equation?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo