$A$ large increase in the rate of reaction for a small increase in temperature is due to:

  • A
    Increase in the number of collisions
  • B
    Increase in the number of activated molecules
  • C
    Decrease in the activation energy
  • D
    Decrease in the mean free path

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Similar Questions

For an exothermic reaction,the following two steps are involved:
Step $1$: $A + B \to I$ $(slow)$
Step $2$: $I \to AB$ $(fast)$
Which of the following graphs correctly represents this reaction?

Which of the following graphs of $\log \, K \rightarrow 1/T$ can be used to calculate the activation energy?

Which of the following graphs for $\ln k$ versus $\frac{1}{T}$ is correct?

For an endothermic reaction $X \rightarrow Y$,the activation energies for the forward and backward reactions are $E_f$ and $E_b$ respectively. Then,in general:

The reason for almost doubling the rate of reaction on increasing the temperature of the reaction system by $10 \, ^\circ C$ is

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