Precipitation of CaF_2 (K_{sp} = 1.7 times 10 | vedclass

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Question

(B) When equal volumes are mixed,the concentration of each ion is halved.For $CaF_2$,the ionic product $Q_{sp} = [Ca^{2+}][F^-]^2$.Precipitation occur

Vedclass · Accepted Answer

$10^{-2} \, M \, Ca^{2+} + 10^{-3} \, M \, F^{-}$

Vedclass · Answer

(B) When equal volumes are mixed,the concentration of each ion is halved.For $CaF_2$,the ionic product $Q_{sp} = [Ca^{2+}][F^-]^2$.Precipitation occurs if $Q_{sp} > K_{sp}$.For option $B$: $[Ca^{2+}] = \frac{10^{-2}}{2} = 5 	imes 10^{-3} \, M$ and $[F^-] = \frac{10^{-3}}{2} = 5 	imes 10^{-4} \, M$.$Q_{sp} = (5 	imes 10^{-3}) 	imes (5 	imes 10^{-4})^2 = 5 	imes 10^{-3} 	imes 25 	imes 10^{-8} = 1.25 	imes 10^{-9}$.Since $1.25 	imes 10^{-9} > 1.7 	imes 10^{-10}$,precipitation occurs.

Precipitation of $CaF_2$ $(K_{sp} = 1.7 \times 10^{-10})$ occurs when equal volumes of which of the following are mixed?

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