The $K_{sp}$ expression for $Ca_3(PO_4)_2$ is:
- A$[Ca^{+2}] [PO_4^{-3}]$
- B$[Ca^{+2}]^3 [PO_4^{-3}]^2$
- C$[Ca^{+2}]^2 [PO_4^{-3}]^3$
- D$[Ca^{+2}] [PO_4^{-3}]^2$
Explore More
Similar Questions
Calculate the molar solubility of calcium hydroxide $Ca(OH)_2$ in $0.10 \ M \ NaOH$ solution. The solubility product constant $(K_{sp})$ of calcium hydroxide is $5.5 \times 10^{-6}$.
DifficultTS EAMCET 2020
View SolutionIf $S$ and $K_{sp}$ are respectively solubility and solubility product of a sparingly soluble binary electrolyte,then
Medium
View SolutionWhich of the following substances is insoluble in dilute hydrochloric acid?
Easy
View Solution$K_{sp}$ for $Cr(OH)_3$ is $2.7 \times 10^{-31}$. What is its solubility in moles / litre?
Medium
View SolutionIf the solubility products of $AgCl$ and $AgBr$ are $1.0 \times 10^{-10}$ and $3.5 \times 10^{-13}$ respectively,then the relation between the solubilities (denoted by the symbol $S$) of these salts can correctly be represented as:
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo