If the dissociation constants of ammonium hyd | vedclass

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(C) For a salt of a weak acid and a weak base,the degree of hydrolysis $(h)$ is given by the formula: $h = \sqrt{\frac{K_w}{K_a 	imes K_b}}$Given: $K

Vedclass · Accepted Answer

$0.55 	imes 10^{-2}$

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(C) For a salt of a weak acid and a weak base,the degree of hydrolysis $(h)$ is given by the formula: $h = \sqrt{\frac{K_w}{K_a 	imes K_b}}$Given: $K_w = 10^{-14}$,$K_a = 1.8 	imes 10^{-5}$,$K_b = 1.8 	imes 10^{-5}$Substituting the values: $h = \sqrt{\frac{10^{-14}}{1.8 	imes 10^{-5} 	imes 1.8 	imes 10^{-5}}}$$h = \sqrt{\frac{10^{-14}}{3.24 	imes 10^{-10}}} = \sqrt{\frac{1}{3.24} 	imes 10^{-4}}$$h = \frac{1}{1.8} 	imes 10^{-2} \approx 0.555 	imes 10^{-2}$Thus,the degree of hydrolysis is $0.55 	imes 10^{-2}$.

If the dissociation constants of ammonium hydroxide $(NH_4OH)$ and acetic acid $(CH_3COOH)$ are both $1.8 \times 10^{-5}$ and $K_w = 10^{-14}$,what is the degree of hydrolysis of $CH_3COONH_4$?

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