The solubility of an electrolyte of type $MX_2$ is $0.5 \times 10^{-4} \ mol/L$. Find the $K_{sp}$ of the electrolyte.

If the solubility of salts $M_2X$,$QY_2$,and $PZ_2$ is the same,what is the relationship between their $K_{sp}$ values?

Assign $A, B, C, D$ from the given type of reaction.
$AlCl_3 + 3NaOH \longrightarrow Al(OH)_3 \downarrow + 3NaCl$

The $K_{sp}$ for $BaSO_4$ at $25\ ^\circ C$ is $1.1 \times 10^{-10}$. To make the new solubility equal to $1.1 \times 10^{-8} \ M$,it is necessary to use a solution of $Na_2SO_4$ of the following concentration (in $M$):

The solubility of $CdSO_{4}$ in water is $8.0 \times 10^{-4} \ mol \ L^{-1}$. Its solubility in $0.01 \ M \ H_{2}SO_{4}$ solution is $..... \ \times 10^{-6} \ mol \ L^{-1}$.
(Round off to the Nearest integer) (Assume that solubility is much less than $0.01 \ M$)

Explain the equilibrium involving the dissolution of a solid in a liquid.