The solubility products of some sparingly sol | vedclass

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(A) For $(a)$ $MX$: $K_{sp} = s^2 = 4.0 	imes 10^{-20} \implies s = \sqrt{4.0 	imes 10^{-20}} = 2.0 	imes 10^{-10} \ M$.For $(b)$ $P_2Q$: $K_{sp} =

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$a < c < b$

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(A) For $(a)$ $MX$: $K_{sp} = s^2 = 4.0 	imes 10^{-20} \implies s = \sqrt{4.0 	imes 10^{-20}} = 2.0 	imes 10^{-10} \ M$.For $(b)$ $P_2Q$: $K_{sp} = 4s^3 = 3.2 	imes 10^{-11} \implies s^3 = 0.8 	imes 10^{-11} = 8 	imes 10^{-12} \implies s = 2 	imes 10^{-4} \ M$.For $(c)$ $LY_3$: $K_{sp} = 27s^4 = 2.7 	imes 10^{-31} \implies s^4 = 0.1 	imes 10^{-31} = 1 	imes 10^{-32} \implies s = 10^{-8} \ M$.Comparing the molar solubilities: $2.0 	imes 10^{-10} Thus,the increasing order is $a < c < b$.

The solubility products of some sparingly soluble electrolytes are given below. The increasing order of their molar solubility is:
$(a)$ Formula: $MX$,$K_{sp} = 4.0 \times 10^{-20}$
$(b)$ Formula: $P_2Q$,$K_{sp} = 3.2 \times 10^{-11}$
$(c)$ Formula: $LY_3$,$K_{sp} = 2.7 \times 10^{-31}$

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The solubility products of some sparingly soluble electrolytes are given below. The increasing order of their molar solubility is:$(a)$ Formula: $MX$,$K_{sp} = 4.0 \times 10^{-20}$$(b)$ Formula: $P_2Q$,$K_{sp} = 3.2 \times 10^{-11}$$(c)$ Formula: $LY_3$,$K_{sp} = 2.7 \times 10^{-31}$