If the solubility product of AB_2 is 4 times | vedclass

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Question

(C) For a salt of type $AB_2$,the dissociation is given by: $AB_2(s) \rightleftharpoons A^{2+}(aq) + 2B^-(aq)$.Let the solubility be $S \ mol/L$.Then,

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$1 	imes 10^{-4}$

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(C) For a salt of type $AB_2$,the dissociation is given by: $AB_2(s) ightleftharpoons A^{2+}(aq) + 2B^-(aq)$.Let the solubility be $S \ mol/L$.Then,$[A^{2+}] = S$ and $[B^-] = 2S$.The solubility product expression is: $K_{sp} = [A^{2+}][B^-]^2$.Substituting the values: $K_{sp} = (S)(2S)^2 = 4S^3$.Given $K_{sp} = 4 	imes 10^{-12}$.So,$4S^3 = 4 	imes 10^{-12}$.$S^3 = 10^{-12}$.$S = (10^{-12})^{1/3} = 10^{-4} \ mol/L$.

If the solubility product of $AB_2$ is $4 \times 10^{-12}$,then its solubility is .......?

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