A container contains 5 mol of A and 10 mol | vedclass

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Question

(A) The total number of moles $n_{total} = n_A + n_B = 5 + 10 = 15 \ mol$. According to Dalton's Law of partial pressures,$P_i = x_i 	imes P_{total}$

Vedclass · Accepted Answer

$6 \ atm, 12 \ atm$

Vedclass · Answer

(A) The total number of moles $n_{total} = n_A + n_B = 5 + 10 = 15 \ mol$. According to Dalton's Law of partial pressures,$P_i = x_i 	imes P_{total}$,where $x_i$ is the mole fraction. $x_A = \frac{5}{15} = \frac{1}{3}$ and $x_B = \frac{10}{15} = \frac{2}{3}$. $P_A = x_A 	imes P_{total} = \frac{1}{3} 	imes 18 = 6 \ atm$. $P_B = x_B 	imes P_{total} = \frac{2}{3} 	imes 18 = 12 \ atm$.

$A$ container contains $5 \ mol$ of $A$ and $10 \ mol$ of $B$. The total pressure of the container is $18 \ atm$. What are the partial pressures $P_A$ and $P_B$ respectively?

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