What is the pH of a solution containing 10 , | vedclass

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(D) The reaction is $2NaOH + H_2SO_4 ightarrow Na_2SO_4 + 2H_2O$. Number of millimoles of $NaOH = 10 \, mL 	imes 0.1 \, M = 1 \, mmol$. Number of m

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(D) The reaction is $2NaOH + H_2SO_4 ightarrow Na_2SO_4 + 2H_2O$. Number of millimoles of $NaOH = 10 \, mL 	imes 0.1 \, M = 1 \, mmol$. Number of millimoles of $H_2SO_4 = 10 \, mL 	imes 0.05 \, M = 0.5 \, mmol$. Since $2 \, mmol$ of $NaOH$ reacts with $1 \, mmol$ of $H_2SO_4$,$1 \, mmol$ of $NaOH$ will react with $0.5 \, mmol$ of $H_2SO_4$. Both reactants are completely consumed,resulting in a neutral solution. Therefore,the $pH$ of the solution is $7$.

What is the $pH$ of a solution containing $10 \, mL$ of $0.1 \, M \, NaOH$ and $10 \, mL$ of $0.05 \, M \, H_2SO_4$?

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