For the reaction CH_3COOH + H_2O rightlefthar | vedclass

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Question

(B) The equilibrium constant $K$ for a general reversible reaction $aA + bB \rightleftharpoons cC + dD$ is defined as the ratio of the product of the

Vedclass · Accepted Answer

$K = \frac{[H_3O^{+}][CH_3COO^{-}]}{[H_2O][CH_3COOH]}$

Vedclass · Answer

(B) The equilibrium constant $K$ for a general reversible reaction $aA + bB \rightleftharpoons cC + dD$ is defined as the ratio of the product of the concentrations of the products to the product of the concentrations of the reactants,each raised to the power of their stoichiometric coefficients.For the reaction $CH_3COOH + H_2O \rightleftharpoons H_3O^{+} + CH_3COO^{-}$,the expression is:$K = \frac{[H_3O^{+}][CH_3COO^{-}]}{[CH_3COOH][H_2O]}$Comparing this with the given options,option $B$ matches this expression.

For the reaction $CH_3COOH + H_2O \rightleftharpoons H_3O^{+} + CH_3COO^{-}$,the equilibrium constant $K$ is given by:

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