(C) The solubility product expression for $Mg(OH)_2$ is: $K_{sp} = [Mg^{2+}][OH^-]^2$. Given $K_{sp} = 1.0 \times 10^{-11}$ and $[Mg^{2+}] = 0.001 \,

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The solubility product expression for $Mg(OH)_2$ is: $K_{sp} = [Mg^{2+}][OH^-]^2$. Given $K_{sp} = 1.0 \times 10^{-11}$ and $[Mg^{2+}] = 0.001 \, M = 10^{-3} \, M$. Substituting the values: $1.0 \times 10^{-11} = (10^{-3})[OH^-]^2$. $[OH^-]^2 = \frac{1.0 \times 10^{-11}}{10^{-3}} = 10^{-8}$. $[OH^-] = \sqrt{10^{-8}} = 10^{-4} \, M$. Now,$pOH = -\log[OH^-] = -\log(10^{-4}) = 4$. Since $pH + pOH = 14$,we have $pH = 14 - 4 = 10$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Solubility product

Medium

At $25 \, ^\circ C$,the solubility product $(K_{sp})$ of $Mg(OH)_2$ is $1.0 \times 10^{-11}$. What is the minimum $pH$ required to precipitate $Mg(OH)_2$ from a $0.001 \, M \, Mg^{2+}$ solution?

A
$8$
B
$9$
C
$10$
D
$11$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

6-2.Equilibrium-II (Ionic Equilibrium)

Subtopic

Solubility product

If the concentration of $[Ag^{+}]$ in a solution is $1 \times 10^{-6} \ M$,what is the concentration of $[Br^{-}]$? Given that the $K_{sp}$ for $AgBr$ is $4.0 \times 10^{-13}$.

Medium

View Solution

Evaporation of $1 \ L$ of a saturated solution of $CaCO_3$ leaves a residue of $7.0 \ g$. What is the solubility product $(K_{sp})$ for $CaCO_3$?

Medium

View Solution

The salt having the least solubility in water is

Difficult

View Solution

Solubility of an $MX_2$ type electrolyte is $0.5 \times 10^{-4} \ mol/L$,then $K_{sp}$ of electrolyte is

Medium

View Solution

$A$ $2.901 \ L$ saturated solution is formed by $0.08 \ g$ of $CaF_2$ at $298 \ K$. Calculate the $K_{sp}$ of $CaF_2$. (Molar mass of $CaF_2$ is $78 \ g \ mol^{-1}$)

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

At $25 \, ^\circ C$,the solubility product $(K_{sp})$ of $Mg(OH)_2$ is $1.0 \times 10^{-11}$. What is the minimum $pH$ required to precipitate $Mg(OH)_2$ from a $0.001 \, M \, Mg^{2+}$ solution?

Similar Questions

If the concentration of $[Ag^{+}]$ in a solution is $1 \times 10^{-6} \ M$,what is the concentration of $[Br^{-}]$? Given that the $K_{sp}$ for $AgBr$ is $4.0 \times 10^{-13}$.

Evaporation of $1 \ L$ of a saturated solution of $CaCO_3$ leaves a residue of $7.0 \ g$. What is the solubility product $(K_{sp})$ for $CaCO_3$?

The salt having the least solubility in water is

Solubility of an $MX_2$ type electrolyte is $0.5 \times 10^{-4} \ mol/L$,then $K_{sp}$ of electrolyte is

$A$ $2.901 \ L$ saturated solution is formed by $0.08 \ g$ of $CaF_2$ at $298 \ K$. Calculate the $K_{sp}$ of $CaF_2$. (Molar mass of $CaF_2$ is $78 \ g \ mol^{-1}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module