A container at equilibrium contains SO_3, SO_ | vedclass

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(B) The chemical equilibrium reaction is: $2SO_3(g) \rightleftharpoons 2SO_2(g) + O_2(g)$.According to Le Chatelier's principle,if the total pressure

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decrease

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(B) The chemical equilibrium reaction is: $2SO_3(g) \rightleftharpoons 2SO_2(g) + O_2(g)$.According to Le Chatelier's principle,if the total pressure of a system at equilibrium is increased at constant temperature and volume,the equilibrium will shift in the direction that results in a decrease in the number of moles of gas.In this reaction,the reactant side has $2$ moles of gas,and the product side has $2 + 1 = 3$ moles of gas.Increasing the total pressure will shift the equilibrium towards the side with fewer moles of gas,which is the reactant side $(SO_3)$.Therefore,the dissociation of $SO_3$ will decrease.

$A$ container at equilibrium contains $SO_3, SO_2$ and $O_2$. The total pressure in the container is increased while the temperature and volume remain constant. According to Le Chatelier's principle,the dissociation of $SO_3$ will........

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