The oxidation of SO_2 to SO_3 by O_2 is an ex | vedclass

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(B) The given reaction is $2SO_2(g) + O_2(g) ightleftharpoons 2SO_3(g) + 	ext{Heat}$.According to Le Chatelier's principle,for an exothermic reacti

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Temperature decreases and pressure increases

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(B) The given reaction is $2SO_2(g) + O_2(g) ightleftharpoons 2SO_3(g) + 	ext{Heat}$.According to Le Chatelier's principle,for an exothermic reaction,a decrease in temperature shifts the equilibrium in the forward direction to release more heat,thus increasing the yield of $SO_3$.Since the number of moles of gaseous products $(2 \ mol)$ is less than the number of moles of gaseous reactants $(2+1 = 3 \ mol)$,an increase in pressure shifts the equilibrium towards the side with fewer moles (forward direction) to reduce the pressure.Therefore,decreasing the temperature and increasing the pressure will increase the yield of $SO_3$.

The oxidation of $SO_2$ to $SO_3$ by $O_2$ is an exothermic reaction: $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) + \text{Heat}$. The yield of $SO_3$ will increase if:

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