For the reaction 2SO_2(g) + O_2(g) rightlefth | vedclass

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(A) The given reaction is $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$ with $\Delta H^o = -198 \, kJ$.Since $\Delta H^o < 0$,the reaction is exothe

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Decrease in temperature and increase in pressure

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(A) The given reaction is $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$ with $\Delta H^o = -198 \, kJ$.Since $\Delta H^o According to Le Chatelier's principle,for an exothermic reaction,a decrease in temperature favors the forward reaction.For the pressure effect,we look at the change in the number of moles of gas: $\Delta n_g = 2 - (2 + 1) = -1$.Since the number of moles decreases in the forward direction,an increase in pressure favors the forward reaction.Therefore,the favorable conditions are a decrease in temperature and an increase in pressure.

For the reaction $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$,$\Delta H^o = -198 \, kJ$. According to Le Chatelier's principle,the favorable conditions for the forward reaction are:

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