A force overrightarrow F = 6hat i + 2hat j - | vedclass

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(D) The work done $W$ by a force $\overrightarrow F$ during a displacement $\overrightarrow s$ is given by the dot product: $W = \overrightarrow F \cd

Vedclass · Accepted Answer

$2$

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(D) The work done $W$ by a force $\overrightarrow F$ during a displacement $\overrightarrow s$ is given by the dot product: $W = \overrightarrow F \cdot \overrightarrow s$.Given that the work done is zero,we have $W = 0$.Substituting the given vectors: $(6\hat i + 2\hat j - 3\hat k) \cdot (2\hat i - 3\hat j + x\hat k) = 0$.Calculating the dot product: $(6 	imes 2) + (2 	imes -3) + (-3 	imes x) = 0$.$12 - 6 - 3x = 0$.$6 - 3x = 0$.$3x = 6$.$x = 2$.

$A$ force $\overrightarrow F = 6\hat i + 2\hat j - 3\hat k$ acts on a particle,causing a displacement of $\overrightarrow s = 2\hat i - 3\hat j + x\hat k$. If the work done is zero,find the value of $x$.

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