A body of mass 10 kg moves a distance of 10 | vedclass

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(A) Since the body moves with a constant velocity, the net force acting on it is zero.To move the body up the plane at a constant velocity, an externa

Vedclass · Accepted Answer

$500$

Vedclass · Answer

(A) Since the body moves with a constant velocity, the net force acting on it is zero.To move the body up the plane at a constant velocity, an external force $F$ must be applied parallel to the plane to balance the component of gravitational force acting down the plane.$F = Mg \sin 	heta$Given: $M = 10 \ kg$, $g = 10 \ m/s^2$, $	heta = 30^\circ$, $d = 10 \ m$.$F = 10 	imes 10 	imes \sin(30^\circ) = 100 	imes 0.5 = 50 \ N$.The work done by this external force $W = F \cdot d \cdot \cos(0^\circ) = 50 	imes 10 	imes 1 = 500 \ J$.

$A$ body of mass $10 \ kg$ moves a distance of $10 \ m$ with a constant velocity up a smooth inclined plane of angle $\theta = 30^\circ$. Calculate the work done by the external applied force acting parallel to the plane in $J$. $[g = 10 \ m/s^2]$

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