$A$ body of mass $0.50 \ kg$ is moving on a smooth surface with a speed of $2.00 \ m/s$. It collides with another body of mass $1.00 \ kg$ at rest,and they move together as a single body. The energy loss during the collision is ....... $J$.

Two bodies of the same mass $m$ are moving with the same speed $v_0$,but in different directions in a plane. They undergo a completely inelastic collision and move together thereafter with a final speed which is half of their initial speed. The angle between the initial velocities of the two bodies (in degrees) is:

$A$ bullet of mass $m$ moving with a speed $v$ strikes a wooden block of mass $M$ and gets embedded into the block. The final speed is

$A$ body of mass $5 \times 10^{3} \, kg$ moving with speed $2 \, m/s$ collides with a body of mass $15 \times 10^{3} \, kg$ inelastically and sticks to it. The loss in $K.E.$ of the system will be (in $kJ$):

$A$ clay ball of mass $m$ and speed $v$ strikes another metal ball of the same mass $m$,which is at rest. They stick together after the collision. The kinetic energy of the system after the collision is

$A$ neutron of mass $1.67 \times 10^{-27} \ kg$ moving with a velocity of $10^8 \ m/s$ collides with a deuteron at rest and sticks to it. If the mass of the deuteron is $3.34 \times 10^{-27} \ kg$,what will be the velocity of the combined system?