Heat flows through a long metallic rod from o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Under steady-state conditions,the rate of heat flow $H$ through a rod is constant and is given by the formula:$H = \frac{KA(T_1 - T_2)}{L} = \frac

Vedclass · Accepted Answer

Vedclass · Answer

(D) Under steady-state conditions,the rate of heat flow $H$ through a rod is constant and is given by the formula:$H = \frac{KA(T_1 - T_2)}{L} = \frac{KA(T_1 - T_x)}{x}$where $T_1$ is the temperature at the hot end $(x=0)$,$T_2$ is the temperature at the cold end $(x=L)$,and $T_x$ is the temperature at distance $x$.Rearranging the equation for $T_x$:$T_x = T_1 - \left( \frac{T_1 - T_2}{L} ight) x$This is a linear equation of the form $y = mx + c$,where the slope $m = -\frac{T_1 - T_2}{L}$ is negative and constant.Therefore,the temperature $	heta$ decreases linearly with distance $x$,which corresponds to a straight line with a negative slope.

Heat flows through a long metallic rod from one end to the other under steady-state conditions. The variation of temperature $\theta$ with distance $x$ from the hot end is shown in which of the following graphs?

Similar Questions

What is temperature gradient? When is the temperature gradient considered positive and when is it considered negative?

$A$ piece of glass is heated to a high temperature and then allowed to cool. If it cracks,a probable reason for this is the following property of glass:

Why are snow particles poorer conductors of heat than ice?

Four rods of silver,copper,brass,and wood are of the same shape. They are heated together after wrapping a paper on each. The paper will burn first on:

When the two ends of a metal rod are maintained at different temperatures and after some time every point of the rod attains a constant temperature,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module