An ideal heat engine based on the Carnot cycl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The efficiency of a Carnot engine is given by $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ is the source temperature and $T_2$ is the sink temperature

Vedclass · Accepted Answer

$1.2 	imes 10^{4} \, cal$

Vedclass · Answer

(C) The efficiency of a Carnot engine is given by $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ is the source temperature and $T_2$ is the sink temperature in Kelvin.Given: $T_1 = 227 + 273 = 500 \, K$ and $T_2 = 127 + 273 = 400 \, K$.Heat absorbed from the source $Q_1 = 6 	imes 10^{4} \, cal$.The efficiency is also defined as $\eta = \frac{W}{Q_1}$,where $W$ is the net work done.Therefore,$W = Q_1 \left( 1 - \frac{T_2}{T_1} ight)$.Substituting the values: $W = 6 	imes 10^{4} \left( 1 - \frac{400}{500} ight)$.$W = 6 	imes 10^{4} \left( 1 - 0.8 ight) = 6 	imes 10^{4} 	imes 0.2$.$W = 1.2 	imes 10^{4} \, cal$.

An ideal heat engine based on the Carnot cycle operates between temperatures of $227 \, ^\circ C$ and $127 \, ^\circ C$. If it absorbs $6 \times 10^{4} \, cal$ of heat from the high-temperature reservoir,the net work done by the engine is:

Similar Questions

The efficiency of a Carnot cycle is $\frac{1}{6}$. By lowering the temperature of the sink by $65 \ K$,it increases to $\frac{1}{3}$. The initial and final temperatures of the sink are:

$A$ Carnot engine has an efficiency of $1/6$. When the temperature of the sink is reduced by $62\,^{\circ}C$,its efficiency is doubled. The temperatures of the source and the sink are,respectively:

The efficiency of an ideal heat engine working between the freezing point and boiling point of water is ........ $\%$

$A$ scientist claims that their heat engine has an efficiency of $26\%$ when operating between a source temperature of $127^{\circ}C$ and a sink temperature of $27^{\circ}C$. This implies that:

The efficiency of a Carnot engine is $50 \%$ when the temperature of the sink is $500 \ K$. If the efficiency of the Carnot engine is to be increased to $60 \%$,what should be the temperature of the sink,keeping the temperature of the source constant (in $K$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module