When a monoatomic gas is heated at constant p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a monoatomic gas,the molar heat capacity at constant volume is $C_V = \frac{3}{2}R$ and at constant pressure is $C_P = \frac{5}{2}R$.When heat

Vedclass · Accepted Answer

$3/5$

Vedclass · Answer

(B) For a monoatomic gas,the molar heat capacity at constant volume is $C_V = \frac{3}{2}R$ and at constant pressure is $C_P = \frac{5}{2}R$.When heat $\Delta Q$ is supplied at constant pressure,the total heat energy is given by $\Delta Q = \mu C_P \Delta T$.The change in internal energy is given by $\Delta U = \mu C_V \Delta T$.The fraction of heat energy used to increase internal energy is $\frac{\Delta U}{\Delta Q} = \frac{\mu C_V \Delta T}{\mu C_P \Delta T} = \frac{C_V}{C_P}$.Substituting the values,we get $\frac{\Delta U}{\Delta Q} = \frac{3/2 R}{5/2 R} = \frac{3}{5}$.

When a monoatomic gas is heated at constant pressure,what fraction of the heat energy supplied is used to increase the internal energy?

Similar Questions

For an ideal gas,the molar specific heat at constant pressure is $(7/2) R$. Find the ratio of the molar specific heat at constant pressure to the molar specific heat at constant volume.

The specific heat relation for an ideal gas is:

The specific heat of helium at constant volume is $12.6 \,J \,mol^{-1} \,K^{-1}$. The specific heat of helium at constant pressure in $J \,mol^{-1} \,K^{-1}$ is approximately (assume, the universal gas constant, $R=8.314 \,J \,mol^{-1} \,K^{-1}$)

How can specific heat be predicted from the law of equipartition of energy?

The ratio of the specific heats $\frac{C_{p}}{C_{v}}=\gamma$,in terms of degrees of freedom $(n)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module