(B) According to Wien's displacement law, $\lambda_m T = \text{constant}$, which implies $\lambda_m \propto \frac{1}{T}$.Initial temperature $T_1 = 12

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(B) According to Wien's displacement law, $\lambda_m T = \text{constant}$, which implies $\lambda_m \propto \frac{1}{T}$.Initial temperature $T_1 = 1227 + 273 = 1500 \ K$.Initial wavelength $\lambda_1 = 5000 \mathring{A}$.Final temperature $T_2 = 1227 + 1000 + 273 = 2500 \ K$.Using the relation $\frac{\lambda_2}{\lambda_1} = \frac{T_1}{T_2}$:$\lambda_2 = \lambda_1 \times \frac{T_1}{T_2} = 5000 \times \frac{1500}{2500}$.$\lambda_2 = 5000 \times \frac{3}{5} = 3000 \mathring{A}$.

Class 11 Physics 2 Thermal Properties of Matter: Heat Transfer Spectral Emissive Power and Wien's Displacement Law

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$A$ black body emits radiation with maximum intensity at a wavelength of $5000 \mathring{A}$ at a temperature of $1227^\circ C$. If its temperature is increased by $1000^\circ C$, the new wavelength of maximum intensity will be ...... $\mathring{A}$.

A
$2754.8$
B
$3000$
C
$3500$
D
$4000$

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2 Thermal Properties of Matter: Heat Transfer

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Spectral Emissive Power and Wien's Displacement Law

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$A$ black body emits radiation with maximum intensity at a wavelength of $5000 \mathring{A}$ at a temperature of $1227^\circ C$. If its temperature is increased by $1000^\circ C$, the new wavelength of maximum intensity will be ...... $\mathring{A}$.

Similar Questions

The distribution of relative intensity $I(\lambda)$ of blackbody radiation from a solid object versus the wavelength $\lambda$ is shown in the figure. If the Wien displacement law constant is $2.9 \times 10^{-3} \ mK$,what is the approximate temperature of the object in $K$?

Two stars emit maximum radiation at wavelengths $3600 \mathring A$ and $4800 \mathring A$ respectively. The ratio of their temperatures is:

If $\lambda_{m}$ denotes the wavelength at which the radioactive emission from a black body at a temperature $T \; K$ is maximum,then

The black discs $x, y$ and $z$ have radii $1 \ m, 2 \ m$ and $3 \ m$ respectively. The wavelengths corresponding to maximum intensity are $200 \ nm, 300 \ nm$ and $400 \ nm$ respectively. The relation between emissive power $E_{x}, E_{y}$ and $E_{z}$ is

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