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(C) According to the Stefan-Boltzmann law,the intensity of radiation $E$ emitted by a black body is proportional to the fourth power of its absolute t

Vedclass · Accepted Answer

$46$

Vedclass · Answer

(C) According to the Stefan-Boltzmann law,the intensity of radiation $E$ emitted by a black body is proportional to the fourth power of its absolute temperature $T$,i.e.,$E \propto T^4$.Let the initial temperature be $T_1 = T$ and the final temperature be $T_2 = T + 0.10T = 1.1T$.The ratio of the intensities is given by $\frac{E_2}{E_1} = \left( \frac{T_2}{T_1} ight)^4 = (1.1)^4$.Calculating the value: $(1.1)^4 = 1.4641$.To find the percentage increase: $\frac{\Delta E}{E_1} 	imes 100 = \left( \frac{E_2 - E_1}{E_1} ight) 	imes 100 = (1.4641 - 1) 	imes 100 = 46.41\%$.Rounding to the nearest integer,the intensity increases by $46\%$.

If the temperature of a perfectly black body is increased by $10\%$,the intensity of radiation emitted by its surface will increase by ......$\%$.

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