A Carnot engine having an efficiency of 40% t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The efficiency of a Carnot engine is given by $\eta = (1 - \frac{T_L}{T_H}) 	imes 100$,where $T_L$ is the sink temperature and $T_H$ is the sourc

Vedclass · Accepted Answer

$750$

Vedclass · Answer

(C) The efficiency of a Carnot engine is given by $\eta = (1 - \frac{T_L}{T_H}) 	imes 100$,where $T_L$ is the sink temperature and $T_H$ is the source temperature.For the first case: $40 = (1 - \frac{T_L}{500}) 	imes 100$.$0.4 = 1 - \frac{T_L}{500} \implies \frac{T_L}{500} = 0.6 \implies T_L = 300 \ K$.For the second case,the sink temperature $T_L$ remains constant at $300 \ K$ and efficiency $\eta$ becomes $60\%$:$60 = (1 - \frac{300}{T_H'}) 	imes 100$.$0.6 = 1 - \frac{300}{T_H'} \implies \frac{300}{T_H'} = 0.4$.$T_H' = \frac{300}{0.4} = 750 \ K$.

$A$ Carnot engine having an efficiency of $40\%$ takes heat from a source maintained at a temperature of $500 \ K$. If the efficiency is to be increased to $60\%$ while keeping the sink temperature constant,what should be the new source temperature in $K$?

Similar Questions

In practice,all heat engines have an efficiency less than that of a Carnot engine because

$300 \, cal$ of heat is given to a heat engine and it rejects $225 \, cal$ of heat. If the source temperature is $227^{\circ} C$,then the temperature of the sink will be . . . . . . $^{\circ} C$.

$A$ Carnot engine $A$ working between temperatures $600 \ K$ and $T$ $(T < 600 \ K)$ and another Carnot engine $B$ working between temperatures $T$ $(T > 400 \ K)$ and $400 \ K$ are connected in series. If the work done by both the engines is the same, then $T =$ (in $K$)

An ideal heat engine exhausting heat at $77^{\circ}C$ is to have a $30\%$ efficiency. It must take heat at ...... $^{\circ}C$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module