During an experiment,it takes 10 text{ minute | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $m$ be the mass of water. The heat required to raise the temperature from $0 	ext{ °C}$ to $100 	ext{ °C}$ is $Q_1 = m \cdot c \cdot \Delta

Vedclass · Accepted Answer

$550$

Vedclass · Answer

(C) Let $m$ be the mass of water. The heat required to raise the temperature from $0 	ext{ °C}$ to $100 	ext{ °C}$ is $Q_1 = m \cdot c \cdot \Delta T = m \cdot 1 \cdot (100 - 0) = 100m 	ext{ cal}$.Given that this process takes $10 	ext{ minutes}$,the rate of heat supply is $P = \frac{100m}{10} = 10m 	ext{ cal/min}$.Now,the water is converted into steam at $100 	ext{ °C}$ in $55 	ext{ minutes}$. The heat required for this phase change is $Q_2 = m \cdot L$.The heat supplied in $55 	ext{ minutes}$ is $Q_2 = P 	imes 55 = 10m 	imes 55 = 550m 	ext{ cal}$.Equating $Q_2 = mL$,we get $mL = 550m$,which implies $L = 550 	ext{ cal/g}$.

Column-$I$	Column-$II$
$(a)$ Latent heat of vaporization $L_V$	$(i)$ $22.6 \times 10^5 \, J/kg$
$(b)$ Latent heat of fusion $L_f$	$(ii)$ $33.3 \times 10^5 \, J/kg$
	$(iii)$ $3.33 \times 10^5 \, J/kg$

During an experiment,it takes $10 \text{ minutes}$ to raise the temperature of water from $0 \text{ °C}$ to $100 \text{ °C}$,and then it takes another $55 \text{ minutes}$ for the water to completely convert into steam. The value of the latent heat of vaporization is ....... $\text{cal/g}$.

Similar Questions

Explain the process of change in the state of matter by heating or cooling it.

$Assertion :$ Melting of a solid causes no change in internal energy.
$Reason :$ Latent heat is the heat required to melt a unit mass of a solid.

Explain the process of melting of ice with an explanation of freezing,melting,and melting point.

The graph signifies:

Vedclass Test Series

Exam Paper Generator

Online Exam Module