When the angle of incidence is 74^{circ},the | vedclass

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(A) The formula for Maximum Usable Frequency $(MUF)$ is given by: $	ext{MUF} = f_c \sec(i)$,where $f_c$ is the critical frequency and $i$ is the angl

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$181$

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(A) The formula for Maximum Usable Frequency $(MUF)$ is given by: $	ext{MUF} = f_c \sec(i)$,where $f_c$ is the critical frequency and $i$ is the angle of incidence.Given: $f_c = 50 	ext{ MHz}$ and $i = 74^{\circ}$.$	ext{MUF} = 50 	imes \sec(74^{\circ})$.Since $\cos(74^{\circ}) \approx 0.2756$,then $\sec(74^{\circ}) = \frac{1}{\cos(74^{\circ})} \approx \frac{1}{0.2756} \approx 3.628$.$	ext{MUF} = 50 	imes 3.628 = 181.4 	ext{ MHz}$.Rounding to the nearest provided option,the correct value is $181.5 	ext{ MHz}$.

When the angle of incidence is $74^{\circ}$,the critical frequency of the $F$ layer is $50 \text{ MHz}$. What is the Maximum Usable Frequency $(MUF)$ in $\text{ MHz}$ (in $.5$)?

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