Pure benzene freezes at $5.3^oC$. $A$ solution of $0.223 \ g$ of $C_6H_5CH_2COOH$ in $4.49 \ g$ of benzene freezes at $4.47^oC$. Given $K_f = 5.12 \ K \ kg/mol$,what can be concluded from this?

  • A
    Phenylacetic acid $(C_6H_5CH_2COOH)$ remains as a monomer in benzene.
  • B
    Phenylacetic acid undergoes partial ionization in benzene.
  • C
    Phenylacetic acid undergoes complete ionization in benzene.
  • D
    Phenylacetic acid forms a dimer in benzene.

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Pure benzene freezes at $5.3\,^oC$. $A$ solution of $0.223\, g$ of phenylacetic acid $(C_6H_5CH_2COOH)$ in $4.4\, g$ of benzene $(K_f = 5.12\, K\, kg\, mol^{-1})$ freezes at $4.47\,^oC$. From this,it can be concluded that phenylacetic acid ........

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