Which solution has the maximum normality?

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(C) To find the normality $(N)$ of each solution:$A$: $8 \ g$ $KOH$ per liter. Molar mass of $KOH = 56 \ g/mol$. $N = \frac{8/56}{1} = 0.143 \ N$.$B$:

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$6 \ g$ $NaOH$ per $100 \ mL$

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(C) To find the normality $(N)$ of each solution:$A$: $8 \ g$ $KOH$ per liter. Molar mass of $KOH = 56 \ g/mol$. $N = \frac{8/56}{1} = 0.143 \ N$.$B$: $1 \ N$ phosphoric acid is given as $1 \ N$.$C$: $6 \ g$ $NaOH$ per $100 \ mL = 60 \ g$ per liter. Molar mass of $NaOH = 40 \ g/mol$. $N = \frac{60/40}{1} = 1.5 \ N$.$D$: $0.5 \ M$ $H_2SO_4$. $N = M 	imes 	ext{valency factor} = 0.5 	imes 2 = 1.0 \ N$.Comparing the values: $0.143, 1, 1.5, 1.0$. The maximum is $1.5 \ N$.

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