Which of the following has the lowest freezin | vedclass

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(C) The depression in freezing point $(\Delta T_f)$ is a colligative property,which depends on the van't Hoff factor $(i)$.$\Delta T_f = i 	imes K_f

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$1 \ m \ CaCl_2$ solution

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(C) The depression in freezing point $(\Delta T_f)$ is a colligative property,which depends on the van't Hoff factor $(i)$.$\Delta T_f = i 	imes K_f 	imes m$.Since the molality $(m)$ is the same for all solutions,the one with the highest van't Hoff factor $(i)$ will have the greatest depression in freezing point,resulting in the lowest freezing point.For $NaCl$,$i = 2$ $(Na^+ + Cl^-)$.For $KCl$,$i = 2$ $(K^+ + Cl^-)$.For $CaCl_2$,$i = 3$ $(Ca^{2+} + 2Cl^-)$.For $	ext{Urea}$,$i = 1$ (non-electrolyte).Since $CaCl_2$ has the highest value of $i$ $(i = 3)$,it will show the maximum depression in freezing point,thus having the lowest freezing point.

Which of the following has the lowest freezing point?

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