For 0.01 M solutions of urea,NaCl,and Na_2SO | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The depression in freezing point $(\Delta T_f)$ is given by the formula $\Delta T_f = i 	imes K_f 	imes m$. Since the molality $(m)$ and the cry

Vedclass · Accepted Answer

$1 : 2 : 3$

Vedclass · Answer

(C) The depression in freezing point $(\Delta T_f)$ is given by the formula $\Delta T_f = i 	imes K_f 	imes m$. Since the molality $(m)$ and the cryoscopic constant $(K_f)$ are the same for all solutions,$\Delta T_f$ is directly proportional to the van't Hoff factor $(i)$. For urea (non-electrolyte),$i = 1$. For $NaCl$ (dissociates into $Na^+$ and $Cl^-$),$i = 2$. For $Na_2SO_4$ (dissociates into $2Na^+$ and $SO_4^{2-}$),$i = 3$. Thus,the ratio of depression in freezing point is $1 : 2 : 3$.

For $0.01 \ M$ solutions of urea,$NaCl$,and $Na_2SO_4$,the ratio of their depression in freezing point is .......

Similar Questions

$A^{2+}$,$B^{2+}$ and $C^{-}$ form an ionic complex like $A_{x-2}[B(C)_x]_2$. If the complex is $75 \%$ dissociated in a solvent with $i=4$,the coordination number of $B$ is:

$0.1 \ m$ solutions of sodium sulphate,urea,and sodium chloride are taken. The correct ratio of the elevation of boiling point of these solutions is

For a $0.1 \ M \ Ba(NO_3)_2$ solution, the van't Hoff factor is $2.74$. The degree of dissociation is .............

If a centimolal aqueous solution of $K_{3}[Fe(CN)_{6}]$ has a degree of dissociation of $0.78$,what is the value of the van't Hoff factor?

Which of the following $0.05 \ M$ aqueous solution will have the lowest freezing point?

Vedclass Test Series

Exam Paper Generator

Online Exam Module