If $Raoult's$ law is obeyed,the vapor pressure of the solvent in a solution is proportional to which of the following?

One mole of a non-volatile solute is dissolved in two moles of water. What is the vapor pressure of this solution relative to that of pure water?

Which of the following substances,when dissolved in water,causes the maximum decrease in the vapor pressure of water?

$60 \ g$ of Urea (Mol. wt $60$) was dissolved in $9.9 \ moles$ of water. If the vapour pressure of pure water is $P_o$,the vapour pressure of the solution is: (in $P_o$)

$224 \, mL$ of $SO_{2(g)}$ at $273 \, K$ and $1 \, atm$ is passed through $100 \, mL$ of $0.1 \, M \, NaOH$ solution. The non-volatile solute produced is dissolved in $36 \, g$ of water. The lowering of vapour pressure of the solution (assuming the solution is dilute) $(P^0_{H_2O} = 24 \, mm \, Hg)$ is $x \times 10^{-2} \, mm \, Hg$. The value of $x$ is ...... . (Integer answer)

What is the vapour pressure of a solution containing $0.1 \text{ mol}$ of non-volatile solute dissolved in $16.2 \text{ g}$ water (in $\text{ mmHg}$)? ($P_1^0 = 24 \text{ mmHg}$, molar mass of water $18 \text{ g mol}^{-1}$)