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Question

(C) According to Raoult's law for non-volatile solutes:
$(1)$ The decrease in vapour pressure $(\Delta P = P_A^o - P_A)$ is equal to $P_A^o 	ime

Vedclass · Accepted Answer

$FTTF$

Vedclass · Answer

(C) According to Raoult's law for non-volatile solutes:
$(1)$ The decrease in vapour pressure $(\Delta P = P_A^o - P_A)$ is equal to $P_A^o 	imes \chi_B$. This is not equal to the mole fraction of the solute $(\chi_B)$. So,statement $(1)$ is $F$.
$(2)$ The relative lowering of vapour pressure is $\frac{P_A^o - P_A}{P_A^o} = \chi_B$. Since $\chi_B = \frac{n_B}{n_A + n_B}$,for dilute solutions,it is proportional to the amount of solute $(n_B)$. So,statement $(2)$ is $T$.
$(3)$ The relative lowering of vapour pressure is equal to the mole fraction of the solute $(\chi_B)$. So,statement $(3)$ is $T$.
$(4)$ The vapour pressure of the solution is $P_A = P_A^o 	imes \chi_A$. It is not equal to the mole fraction of the solvent $(\chi_A)$ unless $P_A^o = 1$. So,statement $(4)$ is $F$.
Thus,the sequence is $FTTF$.

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