Which of the following aqueous solutions will | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The depression in freezing point is given by $\Delta T_f = i 	imes K_f 	imes m$. Since $K_f$ and $m$ are constant for all solutions,the depressi

Vedclass · Accepted Answer

Urea

Vedclass · Answer

(A) The depression in freezing point is given by $\Delta T_f = i 	imes K_f 	imes m$. Since $K_f$ and $m$ are constant for all solutions,the depression in freezing point depends on the van't Hoff factor $(i)$. Lower $i$ value leads to a smaller depression in freezing point,which corresponds to a higher freezing point. $i$ values are: Urea: $i = 1$ $BaCl_2$: $i = 3$ $KBr$: $i = 2$ $Al_2(SO_4)_3$: $i = 5$ Since urea has the lowest $i$ value,it will have the minimum depression in freezing point and thus the highest freezing point.

Which of the following aqueous solutions will have the highest freezing point?

Similar Questions

For the dissociation of $Na_2SO_4$,how is the degree of dissociation $\alpha$ used to calculate the van't Hoff factor $(i)$?

The freezing point of a solution prepared by adding $8.1 \ g$ of $HBr$ ($90\%$ ionized) to $100 \ g$ of water is $...... \ ^\circ C$. (Given $K_f$ for water $= 1.86 \ K \ kg \ mol^{-1}$)

In an aqueous solution of $NaCl$,the mole fraction of the solvent is $0.9$. Then,the relative lowering in vapour pressure will be ......... $atm$.

The addition of a polar solvent to a solid electrolyte results in:

$2 \ m$ aqueous solution of an electrolyte $X_3Y_2$ is $25\%$ ionized. The boiling point of the solution is .......... $K.$ ($K_b$ for $H_2O = 0.52 \ K \ kg/mol$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module