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(C) For isotonic solutions,the molar concentrations are equal at the same temperature. $Molar \ mass \ of \ sucrose \ (C_{12}H_{22}O_{11}) = 342 \ g/m

Vedclass · Accepted Answer

$18$

Vedclass · Answer

(C) For isotonic solutions,the molar concentrations are equal at the same temperature. $Molar \ mass \ of \ sucrose \ (C_{12}H_{22}O_{11}) = 342 \ g/mol$. $Molar \ concentration \ of \ sucrose = \frac{34.2 \ g/L}{342 \ g/mol} = 0.1 \ mol/L$. For the glucose solution to be isotonic,its molar concentration must also be $0.1 \ mol/L$. $Molar \ mass \ of \ glucose \ (C_6H_{12}O_6) = 180 \ g/mol$. $Concentration \ of \ glucose = 0.1 \ mol/L 	imes 180 \ g/mol = 18 \ g/L$.

At $17^\circ C$,the osmotic pressure of an aqueous solution of sucrose $(C_{12}H_{22}O_{11})$ containing $34.2 \ g/L$ is $P$. What concentration of glucose $(C_6H_{12}O_6)$ in $g/L$ would be isotonic with this solution?

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