$A$ regular square plate is shown in the figure. Four identical squares are removed from its corners. Where will the $C.M.$ (Centre of Mass) be located if squares $1$ and $2$ are removed?

$A$ circular hole of radius $3 \text{ cm}$ is cut out from a uniform circular disc of radius $6 \text{ cm}$. The centre of the hole is at $3 \text{ cm}$ from the centre of the original disc. The distance of the centre of gravity of the resulting flat body from the centre of the original disc is: (in $\text{ cm}$)

From a uniform square plate,one-fourth part is removed as shown. The centre of mass of the remaining part will lie on:

$A$ semicircular portion of radius $r$ is cut from a uniform rectangular plate as shown in the figure. The distance of the centre of mass $C$ of the remaining plate from point $O$ is:

The centre of mass of a solid hemisphere of radius $8 \, cm$ is $X \, cm$ from the centre of the flat surface. Then the value of $X$ is $......$

From a uniform disk of radius $R$,a circular hole of radius $R/2$ is cut out. The centre of the hole is at $R/2$ from the centre of the original disc. Locate the centre of gravity of the resulting flat body.