The P-T graph shows a gas being heated. Durin | vedclass

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(C) From the ideal gas equation,$PV = \mu RT$,we can write $V = \frac{\mu RT}{P}$,which implies $V \propto \frac{T}{P}$.In the given $P-T$ graph,the l

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increases.

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(C) From the ideal gas equation,$PV = \mu RT$,we can write $V = \frac{\mu RT}{P}$,which implies $V \propto \frac{T}{P}$.In the given $P-T$ graph,the line representing the process from $1$ to $2$ passes through the $T$-axis at a positive value (if extended). This means the slope $\frac{P}{T}$ is decreasing as $T$ increases.Since $V \propto \frac{T}{P}$,if the ratio $\frac{P}{T}$ decreases,the ratio $\frac{T}{P}$ must increase.Therefore,the volume $V$ of the gas increases during the process from $1$ to $2$.

The $P-T$ graph shows a gas being heated. During this process from point $1$ to $2$,the volume of the gas:

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