(A) The average kinetic energy of an ideal gas is given by $E = \frac{3}{2}kT$,which implies $E \propto T$.First,convert the temperatures from Celsius

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(A) The average kinetic energy of an ideal gas is given by $E = \frac{3}{2}kT$,which implies $E \propto T$.First,convert the temperatures from Celsius to Kelvin:$T_1 = 27 + 273 = 300 \ K$$T_2 = 327 + 273 = 600 \ K$Using the proportionality $E \propto T$,we have:$\frac{E_2}{E_1} = \frac{T_2}{T_1}$$\frac{E_2}{E_1} = \frac{600 \ K}{300 \ K} = 2$Therefore,$E_2 = 2E_1$.

Class 11 Physics Kinetic Theory of Gases Pressure and Energy

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The kinetic energy of an ideal gas at $27^{\circ}C$ is $E_1$. If the temperature is increased to $327^{\circ}C$,what will be the new kinetic energy?

A
$2E_1$
B
$\frac{1}{2}E_1$
C
$\sqrt{2}E_1$
D
$\frac{1}{\sqrt{2}}E_1$

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Kinetic Theory of Gases

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Pressure and Energy

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The kinetic energy of an ideal gas at $27^{\circ}C$ is $E_1$. If the temperature is increased to $327^{\circ}C$,what will be the new kinetic energy?

Similar Questions

At which of the following temperatures would the molecules of a gas have twice the average kinetic energy they have at $20^{\circ}C$ (in $^{\circ}C$)?

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