A container holds 1 mole of O_2 (molar mass 3 | vedclass

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(C) The ideal gas equation is given by $PV = nRT$,where $P$ is pressure,$V$ is volume,$n$ is the number of moles,$R$ is the universal gas constant,and

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$2P$

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(C) The ideal gas equation is given by $PV = nRT$,where $P$ is pressure,$V$ is volume,$n$ is the number of moles,$R$ is the universal gas constant,and $T$ is the absolute temperature.For the first container: $P_1 V_1 = n_1 R T_1$. Given $n_1 = 1$,$T_1 = T$,and $P_1 = P$,we have $PV = RT$ (Equation $1$).For the second container: $P_2 V_2 = n_2 R T_2$. Given $n_2 = 1$,$T_2 = 2T$,and the containers are identical,so $V_2 = V_1 = V$.Substituting these values: $P_2 V = (1) R (2T) = 2RT$ (Equation $2$).Dividing Equation $2$ by Equation $1$: $\frac{P_2 V}{PV} = \frac{2RT}{RT}$.This simplifies to $\frac{P_2}{P} = 2$,which gives $P_2 = 2P$.

$A$ container holds $1$ mole of $O_2$ (molar mass $32$) at temperature $T$. The pressure is $P$. Another identical container holds $1$ mole of $He$ (molar mass $4$) at temperature $2T$. Find the pressure in the second container.

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