A fixed amount of gas has a volume V at const | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The root mean square speed is given by $v_{rms} = \sqrt{\frac{3RT}{M}}$.Since $M$ and $R$ are constant,$v_{rms} \propto \sqrt{T}$.Given that the n

Vedclass · Accepted Answer

$4V$

Vedclass · Answer

(D) The root mean square speed is given by $v_{rms} = \sqrt{\frac{3RT}{M}}$.Since $M$ and $R$ are constant,$v_{rms} \propto \sqrt{T}$.Given that the new root mean square speed $v'_{rms} = 2v_{rms}$,we have:$\frac{v'_{rms}}{v_{rms}} = \sqrt{\frac{T'}{T}} \implies 2 = \sqrt{\frac{T'}{T}} \implies \frac{T'}{T} = 4 \implies T' = 4T$.According to Charles's Law,for a fixed amount of gas at constant pressure,$V \propto T$.Therefore,$\frac{V'}{V} = \frac{T'}{T} = 4$.Thus,the new volume $V' = 4V$.

$A$ fixed amount of gas has a volume $V$ at constant pressure. If the temperature of the gas is increased such that the $v_{rms}$ of the molecules doubles,then its new volume will be .......

Similar Questions

$A$ graph between volume $V$ and absolute temperature $T$ is obtained when a given mass of a gas is heated. During the heating process from state-$1$ to state-$2$,the pressure

What is Boltzmann's constant?

What is the nature of the $P$ versus $1/V$ graph at a constant temperature?

For an ideal gas with pressure $P$,temperature $T$,and volume $V$,where the mass of each molecule is $m$,what is the density of the gas? ($k$ is the Boltzmann constant)

For an ideal gas,the density of the gas is $\varrho_0$ when temperature and pressure of the gas are $T_0$ and $P_0$ respectively. When the temperature of the gas is $2 T_0$,its pressure becomes $3 P_0$. The new density will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module