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(C) Oxygen $(O_2)$ is a diatomic molecule. As a rigid rotator,it has $5$ degrees of freedom ($3$ translational and $2$ rotational).The number of moles

Vedclass · Accepted Answer

$3.8 	imes 10^4 \, J$

Vedclass · Answer

(C) Oxygen $(O_2)$ is a diatomic molecule. As a rigid rotator,it has $5$ degrees of freedom ($3$ translational and $2$ rotational).The number of moles $n$ in $200 \, g$ of $O_2$ is given by $n = \frac{	ext{mass}}{	ext{molar mass}} = \frac{200}{32} = 6.25 \, 	ext{mol}$.The total thermal energy $U$ is given by $U = n \cdot \frac{f}{2} \cdot R \cdot T$,where $f = 5$,$R = 8.314 \, J \cdot mol^{-1} \cdot K^{-1}$,and $T = 27 + 273 = 300 \, K$.$U = 6.25 	imes \frac{5}{2} 	imes 8.314 	imes 300$$U = 6.25 	imes 2.5 	imes 8.314 	imes 300 = 38953.125 \, J \approx 3.9 	imes 10^4 \, J$.Given the options provided,the closest value is $3.8 	imes 10^4 \, J$.

The total thermal energy associated with $200 \, g$ of oxygen at $27 \, ^\circ C$ is ......... $J$. (Assume oxygen molecules as rigid rotators.)

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