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(A) For an electron in a hydrogen atom,the potential energy $U$ is given by $U = -\frac{ke^2}{r}$,which means $U \propto -\frac{1}{r}$.The kinetic ene

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Potential energy increases and kinetic energy decreases.

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(A) For an electron in a hydrogen atom,the potential energy $U$ is given by $U = -\frac{ke^2}{r}$,which means $U \propto -\frac{1}{r}$.The kinetic energy $K$ is given by $K = \frac{ke^2}{2r}$,which means $K \propto \frac{1}{r}$.When the electron jumps from the ground state to an excited state,the principal quantum number $n$ increases,which implies the orbital radius $r$ increases.As $r$ increases,the kinetic energy $K$ decreases.Since $U$ is negative and proportional to $-1/r$,as $r$ increases,the magnitude of $U$ decreases,making $U$ less negative (i.e.,it increases towards zero).Therefore,the potential energy increases and the kinetic energy decreases.

In a hydrogen atom,when an electron jumps from the ground state to an excited state,the electron's ...

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