Find the ratio of the radii of the nuclei _{1 | vedclass

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(C) The radius of a nucleus is given by the relation $R = R_0 A^{1/3}$,where $R_0$ is a constant and $A$ is the mass number.Therefore,the ratio of the

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$3 : 5$

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(C) The radius of a nucleus is given by the relation $R = R_0 A^{1/3}$,where $R_0$ is a constant and $A$ is the mass number.Therefore,the ratio of the radii of two nuclei is given by $\frac{R_1}{R_2} = \left( \frac{A_1}{A_2} \right)^{1/3}$.For $_{13}Al^{27}$,the mass number $A_1 = 27$.For $_{52}Te^{125}$,the mass number $A_2 = 125$.Substituting these values into the ratio formula:$\frac{R_{Al}}{R_{Te}} = \left( \frac{27}{125} \right)^{1/3} = \left( \frac{3^3}{5^3} \right)^{1/3} = \frac{3}{5}$.Thus,the ratio is $3 : 5$.

Find the ratio of the radii of the nuclei $_{13}Al^{27}$ and $_{52}Te^{125}$.

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