An X-ray tube operates at 50 , kV and 20 , mA | vedclass

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(A) The minimum wavelength is given by $\lambda_{	ext{min}} = \frac{hc}{eV} = \frac{12400}{50 	imes 10^3} \, \mathring{A} = 0.248 \, \mathring{A} \a

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$1, 3, 4$

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(A) The minimum wavelength is given by $\lambda_{	ext{min}} = \frac{hc}{eV} = \frac{12400}{50 	imes 10^3} \, \mathring{A} = 0.248 \, \mathring{A} \approx 0.25 \, \mathring{A}$. Thus,statement $(4)$ is correct.For the target material,a high melting point is required to prevent it from melting under intense heat,so statement $(1)$ is correct. High thermal conductivity is required to dissipate heat efficiently,so statement $(2)$ is incorrect.The power supplied is $P = VI = (50 	imes 10^3 \, V) 	imes (20 	imes 10^{-3} \, A) = 1000 \, W$.The power converted to $X$-rays is $1\%$ of $1000 \, W = 10 \, W$.The power converted to heat is $P_H = 99\%$ of $1000 \, W = 990 \, W$.Using $P_H = ms \frac{\Delta 	heta}{\Delta t}$,where $m = 1.0 \, kg$ and $s = 495 \, J \cdot kg^{-1} \cdot ^\circ C^{-1}$:$990 = 1.0 	imes 495 	imes \frac{\Delta 	heta}{\Delta t}$$\frac{\Delta 	heta}{\Delta t} = \frac{990}{495} = 2 \, ^\circ C/s$. Thus,statement $(3)$ is correct.Therefore,statements $(1), (3),$ and $(4)$ are correct.

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